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133020344132133 = 344340114710711
BaseRepresentation
bin11110001111101100110110…
…010111000010001000100101
3122102222121202111100120000020
4132033230312113002020211
5114413401131044212013
61150524411422505353
740006255063220253
oct3617546627021045
9572877674316006
10133020344132133
113942567a47a547
1212b04298135259
13592b9c2b700a3
1424bc30cd5b5d3
15105a26ed83623
hex78fb365c2225

133020344132133 has 4 divisors (see below), whose sum is σ = 177360458842848. Its totient is φ = 88680229421420.

The previous prime is 133020344132077. The next prime is 133020344132147. The reversal of 133020344132133 is 331231443020331.

It is a happy number.

133020344132133 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133020344132133 - 229 = 133019807261221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133020344132094 and 133020344132103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133020344132173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22170057355353 + ... + 22170057355358.

It is an arithmetic number, because the mean of its divisors is an integer number (44340114710712).

Almost surely, 2133020344132133 is an apocalyptic number.

It is an amenable number.

133020344132133 is a deficient number, since it is larger than the sum of its proper divisors (44340114710715).

133020344132133 is an equidigital number, since it uses as much as digits as its factorization.

133020344132133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44340114710714.

The product of its (nonzero) digits is 46656, while the sum is 33.

Adding to 133020344132133 its reverse (331231443020331), we get a palindrome (464251787152464).

The spelling of 133020344132133 in words is "one hundred thirty-three trillion, twenty billion, three hundred forty-four million, one hundred thirty-two thousand, one hundred thirty-three".

Divisors: 1 3 44340114710711 133020344132133