Base | Representation |
---|---|
bin | 1100000110010010001011… |
… | …1101010001101101110011 |
3 | 1202002200001020022222211212 |
4 | 3001210202331101231303 |
5 | 3220420200123020103 |
6 | 44142522300230335 |
7 | 2542021305101663 |
oct | 301444275215563 |
9 | 52080036288755 |
10 | 13302100204403 |
11 | 426943086470a |
12 | 15aa05253b3ab |
13 | 7564c8946c0a |
14 | 33db7a0681a3 |
15 | 1810413ed7d8 |
hex | c1922f51b73 |
13302100204403 has 2 divisors, whose sum is σ = 13302100204404. Its totient is φ = 13302100204402.
The previous prime is 13302100204397. The next prime is 13302100204429. The reversal of 13302100204403 is 30440200120331.
13302100204403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30440200120331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13302100204403 - 214 = 13302100188019 is a prime.
It is not a weakly prime, because it can be changed into another prime (13302100204903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651050102201 + 6651050102202.
It is an arithmetic number, because the mean of its divisors is an integer number (6651050102202).
Almost surely, 213302100204403 is an apocalyptic number.
13302100204403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13302100204403 is an equidigital number, since it uses as much as digits as its factorization.
13302100204403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13302100204403 its reverse (30440200120331), we get a palindrome (43742300324734).
The spelling of 13302100204403 in words is "thirteen trillion, three hundred two billion, one hundred million, two hundred four thousand, four hundred three".
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