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13302112000000 = 21156415691
BaseRepresentation
bin1100000110010010001110…
…1010010001100000000000
31202002200002001112021100211
43001210203222101200000
53220420211133000000
644142523401123504
72542021510260325
oct301444352214000
952080061467324
1013302112000000
11426943749093a
1215aa056489594
137564cb216b65
1433db7b858b4c
1518104247d7ba
hexc1923a91800

13302112000000 has 168 divisors, whose sum is σ = 33246815450940. Its totient is φ = 5320832000000.

The previous prime is 13302111999997. The next prime is 13302112000013. The reversal of 13302112000000 is 21120331.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 31792155 + ... + 32207845.

Almost surely, 213302112000000 is an apocalyptic number.

13302112000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13302112000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16623407725470).

13302112000000 is an abundant number, since it is smaller than the sum of its proper divisors (19944703450940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13302112000000 is an frugal number, since it uses more digits than its factorization.

13302112000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 415743 (or 415698 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13302112000000 its reverse (21120331), we get a palindrome (13302133120331).

The spelling of 13302112000000 in words is "thirteen trillion, three hundred two billion, one hundred twelve million", and thus it is an aban number.