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133023013333151 = 526481325266427
BaseRepresentation
bin11110001111101111010101…
…011101001110100010011111
3122102222212122111221000110012
4132033233111131032202133
5114413422112403130101
61150525532333033435
740006411164106364
oct3617572535164237
9572885574830405
10133023013333151
113942681a13a7a7
1212b0490202587b
13592c029b61c86
1424bc4c365446b
15105a379382bbb
hex78fbd574e89f

133023013333151 has 4 divisors (see below), whose sum is σ = 133023043864392. Its totient is φ = 133022982801912.

The previous prime is 133023013333117. The next prime is 133023013333157. The reversal of 133023013333151 is 151333310320331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133023013333151 - 218 = 133023013071007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133023013333157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7368401 + ... + 17898026.

It is an arithmetic number, because the mean of its divisors is an integer number (33255760966098).

Almost surely, 2133023013333151 is an apocalyptic number.

133023013333151 is a deficient number, since it is larger than the sum of its proper divisors (30531241).

133023013333151 is an equidigital number, since it uses as much as digits as its factorization.

133023013333151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30531240.

The product of its (nonzero) digits is 21870, while the sum is 32.

Adding to 133023013333151 its reverse (151333310320331), we get a palindrome (284356323653482).

The spelling of 133023013333151 in words is "one hundred thirty-three trillion, twenty-three billion, thirteen million, three hundred thirty-three thousand, one hundred fifty-one".

Divisors: 1 5264813 25266427 133023013333151