Base | Representation |
---|---|
bin | 11110001111101111011101… |
… | …101110010010101010101000 |
3 | 122102222220000011220020211220 |
4 | 132033233131232102222220 |
5 | 114413422403404233412 |
6 | 1150525554205422040 |
7 | 40006414500005511 |
oct | 3617573556225250 |
9 | 572886004806756 |
10 | 133023152024232 |
11 | 39426890458428 |
12 | 12b0494056a920 |
13 | 592c04c8015c2 |
14 | 24bc4d7c37a08 |
15 | 105a38662b68c |
hex | 78fbddb92aa8 |
133023152024232 has 16 divisors (see below), whose sum is σ = 332557880060640. Its totient is φ = 44341050674736.
The previous prime is 133023152024207. The next prime is 133023152024237. The reversal of 133023152024232 is 232420251320331.
It is a junction number, because it is equal to n+sod(n) for n = 133023152024193 and 133023152024202.
It is not an unprimeable number, because it can be changed into a prime (133023152024237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2771315667148 + ... + 2771315667195.
It is an arithmetic number, because the mean of its divisors is an integer number (20784867503790).
Almost surely, 2133023152024232 is an apocalyptic number.
133023152024232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133023152024232 is an abundant number, since it is smaller than the sum of its proper divisors (199534728036408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133023152024232 is a wasteful number, since it uses less digits than its factorization.
133023152024232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5542631334352 (or 5542631334348 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 33.
The spelling of 133023152024232 in words is "one hundred thirty-three trillion, twenty-three billion, one hundred fifty-two million, twenty-four thousand, two hundred thirty-two".
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