Base | Representation |
---|---|
bin | 11110001111101111100000… |
… | …111000011110000010011011 |
3 | 122102222220010212121220201112 |
4 | 132033233200320132002123 |
5 | 114413423010441231044 |
6 | 1150530003341410535 |
7 | 40006416012335501 |
oct | 3617574070360233 |
9 | 572886125556645 |
10 | 133023205023899 |
11 | 39426908367903 |
12 | 12b04956269a4b |
13 | 592c05a79a158 |
14 | 24bc500cb2671 |
15 | 105a38b0ea09e |
hex | 78fbe0e1e09b |
133023205023899 has 2 divisors, whose sum is σ = 133023205023900. Its totient is φ = 133023205023898.
The previous prime is 133023205023871. The next prime is 133023205023923. The reversal of 133023205023899 is 998320502320331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133023205023899 is a prime.
It is a super-2 number, since 2×1330232050238992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133023205023869) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511602511949 + 66511602511950.
It is an arithmetic number, because the mean of its divisors is an integer number (66511602511950).
Almost surely, 2133023205023899 is an apocalyptic number.
133023205023899 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023205023899 is an equidigital number, since it uses as much as digits as its factorization.
133023205023899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 50.
The spelling of 133023205023899 in words is "one hundred thirty-three trillion, twenty-three billion, two hundred five million, twenty-three thousand, eight hundred ninety-nine".
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