Base | Representation |
---|---|
bin | 11110001111101111101001… |
… | …001100011001101100101011 |
3 | 122102222220111121000100022212 |
4 | 132033233221030121230223 |
5 | 114413423302140413411 |
6 | 1150530025242235335 |
7 | 40006422324515405 |
oct | 3617575114315453 |
9 | 572886447010285 |
10 | 133023344466731 |
11 | 3942697a049314 |
12 | 12b04994ab5b4b |
13 | 592c0806409c4 |
14 | 24bc51560db75 |
15 | 105a39849168b |
hex | 78fbe9319b2b |
133023344466731 has 2 divisors, whose sum is σ = 133023344466732. Its totient is φ = 133023344466730.
The previous prime is 133023344466673. The next prime is 133023344466763. The reversal of 133023344466731 is 137664443320331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133023344466731 is a prime.
It is a super-2 number, since 2×1330233444667312 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133023344466731.
It is not a weakly prime, because it can be changed into another prime (133023344406731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511672233365 + 66511672233366.
It is an arithmetic number, because the mean of its divisors is an integer number (66511672233366).
Almost surely, 2133023344466731 is an apocalyptic number.
133023344466731 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023344466731 is an equidigital number, since it uses as much as digits as its factorization.
133023344466731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7838208, while the sum is 50.
The spelling of 133023344466731 in words is "one hundred thirty-three trillion, twenty-three billion, three hundred forty-four million, four hundred sixty-six thousand, seven hundred thirty-one".
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