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1330234113301 = 7001190006301
BaseRepresentation
bin10011010110111000001…
…000011011110100010101
311201011120022011112200021
4103112320020123310111
5133243304413111201
62455033501345141
7165051304254322
oct23267010336425
94634508145607
101330234113301
11473170528a95
121959848681b1
1398595b2bb02
1448552b35b49
1524908395ea1
hex135b821bd15

1330234113301 has 4 divisors (see below), whose sum is σ = 1330424126604. Its totient is φ = 1330044100000.

The previous prime is 1330234113293. The next prime is 1330234113353. The reversal of 1330234113301 is 1033114320331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 253236407076 + 1076997706225 = 503226^2 + 1037785^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330234113301 - 23 = 1330234113293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330234153301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94996150 + ... + 95010151.

It is an arithmetic number, because the mean of its divisors is an integer number (332606031651).

Almost surely, 21330234113301 is an apocalyptic number.

It is an amenable number.

1330234113301 is a deficient number, since it is larger than the sum of its proper divisors (190013303).

1330234113301 is an equidigital number, since it uses as much as digits as its factorization.

1330234113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190013302.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1330234113301 its reverse (1033114320331), we get a palindrome (2363348433632).

The spelling of 1330234113301 in words is "one trillion, three hundred thirty billion, two hundred thirty-four million, one hundred thirteen thousand, three hundred one".

Divisors: 1 7001 190006301 1330234113301