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133024211021414 = 266512105510707
BaseRepresentation
bin11110001111110000011100…
…110110000010111001100110
3122102222222201222120212212202
4132033300130312002321212
5114413432041010141124
61150530251235414502
740006452646226036
oct3617603466027146
9572888658525782
10133024211021414
1139427284207709
1212b04b97154432
13592c18b02715b
1424bc5987418c6
15105a3e95b35ae
hex78fc1cd82e66

133024211021414 has 4 divisors (see below), whose sum is σ = 199536316532124. Its totient is φ = 66512105510706.

The previous prime is 133024211021413. The next prime is 133024211021459. The reversal of 133024211021414 is 414120112420331.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133024211021413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33256052755352 + ... + 33256052755355.

It is an arithmetic number, because the mean of its divisors is an integer number (49884079133031).

Almost surely, 2133024211021414 is an apocalyptic number.

133024211021414 is a deficient number, since it is larger than the sum of its proper divisors (66512105510710).

133024211021414 is an equidigital number, since it uses as much as digits as its factorization.

133024211021414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66512105510709.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 133024211021414 its reverse (414120112420331), we get a palindrome (547144323441745).

The spelling of 133024211021414 in words is "one hundred thirty-three trillion, twenty-four billion, two hundred eleven million, twenty-one thousand, four hundred fourteen".

Divisors: 1 2 66512105510707 133024211021414