1330243314131 has 2 divisors, whose sum is σ = 1330243314132. Its totient is φ = 1330243314130.

The previous prime is 1330243314079. The next prime is 1330243314149. The reversal of 1330243314131 is 1314133420331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1330243314131 is a prime.

It is a super-2 number, since 2×1330243314131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330243314094 and 1330243314103.

It is not a weakly prime, because it can be changed into another prime (1330243314331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665121657065 + 665121657066.

It is an arithmetic number, because the mean of its divisors is an integer number (665121657066).

Almost surely, 2^{1330243314131} is an apocalyptic number.

1330243314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330243314131 is an equidigital number, since it uses as much as digits as its factorization.

1330243314131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1330243314131 its reverse (1314133420331), we get a palindrome (2644376734462).

The spelling of 1330243314131 in words is "one trillion, three hundred thirty billion, two hundred forty-three million, three hundred fourteen thousand, one hundred thirty-one".