Base | Representation |
---|---|
bin | 10011010110111010010… |
… | …000010010001101111101 |
3 | 11201011122210011211112000 |
4 | 103112322100102031331 |
5 | 133243343022204230 |
6 | 2455041212532513 |
7 | 165052216046214 |
oct | 23267220221575 |
9 | 4634583154460 |
10 | 1330269725565 |
11 | 473189642010 |
12 | 195994781139 |
13 | 985a031a461 |
14 | 4855776607b |
15 | 2490b57cb60 |
hex | 135ba41237d |
1330269725565 has 128 divisors (see below), whose sum is σ = 2697933864960. Its totient is φ = 615596889600.
The previous prime is 1330269725557. The next prime is 1330269725669. The reversal of 1330269725565 is 5655279620331.
1330269725565 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 2 + 6 + 9 + 72 + 5 + 565 = 666.
It is not a de Polignac number, because 1330269725565 - 23 = 1330269725557 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 15771705 + ... + 15855825.
It is an arithmetic number, because the mean of its divisors is an integer number (21077608320).
Almost surely, 21330269725565 is an apocalyptic number.
1330269725565 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1330269725565 is an abundant number, since it is smaller than the sum of its proper divisors (1367664139395).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1330269725565 is a wasteful number, since it uses less digits than its factorization.
1330269725565 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84632 (or 84626 counting only the distinct ones).
The product of its (nonzero) digits is 10206000, while the sum is 54.
The spelling of 1330269725565 in words is "one trillion, three hundred thirty billion, two hundred sixty-nine million, seven hundred twenty-five thousand, five hundred sixty-five".
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