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133029049461409 is a prime number
BaseRepresentation
bin11110001111110100111101…
…001111001110101010100001
3122110000110020011222002210001
4132033310331033032222201
5114414021443130231114
61150532411320140001
740010013600256063
oct3617647517165241
9573013204862701
10133029049461409
11394293373a7252
1212b05b07607601
13592c77c56a1ba
1424bc8d7189733
15105a5ce255374
hex78fd3d3ceaa1

133029049461409 has 2 divisors, whose sum is σ = 133029049461410. Its totient is φ = 133029049461408.

The previous prime is 133029049461379. The next prime is 133029049461449. The reversal of 133029049461409 is 904164940920331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86722004376225 + 46307045085184 = 9312465^2 + 6804928^2 .

It is a cyclic number.

It is not a de Polignac number, because 133029049461409 - 219 = 133029048937121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133029049461409.

It is not a weakly prime, because it can be changed into another prime (133029049461449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66514524730704 + 66514524730705.

It is an arithmetic number, because the mean of its divisors is an integer number (66514524730705).

Almost surely, 2133029049461409 is an apocalyptic number.

It is an amenable number.

133029049461409 is a deficient number, since it is larger than the sum of its proper divisors (1).

133029049461409 is an equidigital number, since it uses as much as digits as its factorization.

133029049461409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5038848, while the sum is 55.

The spelling of 133029049461409 in words is "one hundred thirty-three trillion, twenty-nine billion, forty-nine million, four hundred sixty-one thousand, four hundred nine".