Base | Representation |
---|---|
bin | 10011010110111100001… |
… | …011011110100111001001 |
3 | 11201011202000221120012201 |
4 | 103112330023132213021 |
5 | 133243424304120131 |
6 | 2455044325040201 |
7 | 165053060412211 |
oct | 23267413364711 |
9 | 4634660846181 |
10 | 1330302020041 |
11 | 4731a589a365 |
12 | 1959a3556061 |
13 | 985a6c16907 |
14 | 4855bb71241 |
15 | 2490e30b761 |
hex | 135bc2de9c9 |
1330302020041 has 2 divisors, whose sum is σ = 1330302020042. Its totient is φ = 1330302020040.
The previous prime is 1330302019987. The next prime is 1330302020063. The reversal of 1330302020041 is 1400202030331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 814634410041 + 515667610000 = 902571^2 + 718100^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330302020041 - 27 = 1330302019913 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330302020081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665151010020 + 665151010021.
It is an arithmetic number, because the mean of its divisors is an integer number (665151010021).
Almost surely, 21330302020041 is an apocalyptic number.
It is an amenable number.
1330302020041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330302020041 is an equidigital number, since it uses as much as digits as its factorization.
1330302020041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1330302020041 its reverse (1400202030331), we get a palindrome (2730504050372).
The spelling of 1330302020041 in words is "one trillion, three hundred thirty billion, three hundred two million, twenty thousand, forty-one".
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