133031124413413 has 4 divisors (see below), whose sum is σ = 133032243258828. Its totient is φ = 133030005568000.

The previous prime is 133031124413329. The next prime is 133031124413441. The reversal of 133031124413413 is 314314421130331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11157517242369 + 121873607171044 = 3340287^2 + 11039638^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133031124413413 is a prime.

It is a super-3 number, since 3×133031124413413³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133031124413443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 559244338 + ... + 559482163.

It is an arithmetic number, because the mean of its divisors is an integer number (33258060814707).

Almost surely, 2^{133031124413413} is an apocalyptic number.

It is an amenable number.

133031124413413 is a deficient number, since it is larger than the sum of its proper divisors (1118845415).

133031124413413 is a wasteful number, since it uses less digits than its factorization.

133031124413413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1118845414.

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 133031124413413 its reverse (314314421130331), we get a palindrome (447345545543744).

The spelling of 133031124413413 in words is "one hundred thirty-three trillion, thirty-one billion, one hundred twenty-four million, four hundred thirteen thousand, four hundred thirteen".