Base | Representation |
---|---|
bin | 11110001111110110111001… |
… | …011001100110010011000001 |
3 | 122110000122121100200012012112 |
4 | 132033312321121212103001 |
5 | 114414040224413220213 |
6 | 1150533354132105105 |
7 | 40010116323255431 |
oct | 3617667131462301 |
9 | 573018540605175 |
10 | 133031132554433 |
11 | 3942a206237933 |
12 | 12b063a9165195 |
13 | 592ca21cb8719 |
14 | 24bca53ab42c1 |
15 | 105a6a207cea8 |
hex | 78fdb96664c1 |
133031132554433 has 2 divisors, whose sum is σ = 133031132554434. Its totient is φ = 133031132554432.
The previous prime is 133031132554249. The next prime is 133031132554531. The reversal of 133031132554433 is 334455231130331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 90752163590449 + 42278968963984 = 9526393^2 + 6502228^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133031132554433 is a prime.
It is not a weakly prime, because it can be changed into another prime (133031132559433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515566277216 + 66515566277217.
It is an arithmetic number, because the mean of its divisors is an integer number (66515566277217).
Almost surely, 2133031132554433 is an apocalyptic number.
It is an amenable number.
133031132554433 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031132554433 is an equidigital number, since it uses as much as digits as its factorization.
133031132554433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 583200, while the sum is 41.
Adding to 133031132554433 its reverse (334455231130331), we get a palindrome (467486363684764).
The spelling of 133031132554433 in words is "one hundred thirty-three trillion, thirty-one billion, one hundred thirty-two million, five hundred fifty-four thousand, four hundred thirty-three".
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