Base | Representation |
---|---|
bin | 111101111100101001… |
… | …0101011101010100111 |
3 | 110201101012010111210121 |
4 | 1323321102223222213 |
5 | 4134422022134421 |
6 | 141040325302411 |
7 | 12416433415630 |
oct | 1737122535247 |
9 | 421335114717 |
10 | 133031443111 |
11 | 51466866216 |
12 | 21947b64a07 |
13 | c710c47b58 |
14 | 661dd38887 |
15 | 36d9068d41 |
hex | 1ef94abaa7 |
133031443111 has 4 divisors (see below), whose sum is σ = 152035934992. Its totient is φ = 114026951232.
The previous prime is 133031443057. The next prime is 133031443117. The reversal of 133031443111 is 111344130331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133031443111 - 221 = 133029345959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133031443117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9502245930 + ... + 9502245943.
It is an arithmetic number, because the mean of its divisors is an integer number (38008983748).
Almost surely, 2133031443111 is an apocalyptic number.
133031443111 is a deficient number, since it is larger than the sum of its proper divisors (19004491881).
133031443111 is an equidigital number, since it uses as much as digits as its factorization.
133031443111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19004491880.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 133031443111 its reverse (111344130331), we get a palindrome (244375573442).
The spelling of 133031443111 in words is "one hundred thirty-three billion, thirty-one million, four hundred forty-three thousand, one hundred eleven".
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