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133031505739441 is a prime number
BaseRepresentation
bin11110001111110111001111…
…101001001011111010110001
3122110000200120100212221210111
4132033313033221023322301
5114414042010432130231
61150533455142501321
740010131504265401
oct3617671751137261
9573020510787714
10133031505739441
113942a3879582a1
1212b06492134841
13592ca813cb95a
1424bca8b498801
15105a6c4be64b1
hex78fdcfa4beb1

133031505739441 has 2 divisors, whose sum is σ = 133031505739442. Its totient is φ = 133031505739440.

The previous prime is 133031505739427. The next prime is 133031505739471. The reversal of 133031505739441 is 144937505130331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125971351900416 + 7060153839025 = 11223696^2 + 2657095^2 .

It is a cyclic number.

It is not a de Polignac number, because 133031505739441 - 27 = 133031505739313 is a prime.

It is not a weakly prime, because it can be changed into another prime (133031505739471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515752869720 + 66515752869721.

It is an arithmetic number, because the mean of its divisors is an integer number (66515752869721).

Almost surely, 2133031505739441 is an apocalyptic number.

It is an amenable number.

133031505739441 is a deficient number, since it is larger than the sum of its proper divisors (1).

133031505739441 is an equidigital number, since it uses as much as digits as its factorization.

133031505739441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2041200, while the sum is 49.

The spelling of 133031505739441 in words is "one hundred thirty-three trillion, thirty-one billion, five hundred five million, seven hundred thirty-nine thousand, four hundred forty-one".