Base | Representation |
---|---|
bin | 11110001111110111001111… |
… | …101001001011111010110001 |
3 | 122110000200120100212221210111 |
4 | 132033313033221023322301 |
5 | 114414042010432130231 |
6 | 1150533455142501321 |
7 | 40010131504265401 |
oct | 3617671751137261 |
9 | 573020510787714 |
10 | 133031505739441 |
11 | 3942a3879582a1 |
12 | 12b06492134841 |
13 | 592ca813cb95a |
14 | 24bca8b498801 |
15 | 105a6c4be64b1 |
hex | 78fdcfa4beb1 |
133031505739441 has 2 divisors, whose sum is σ = 133031505739442. Its totient is φ = 133031505739440.
The previous prime is 133031505739427. The next prime is 133031505739471. The reversal of 133031505739441 is 144937505130331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125971351900416 + 7060153839025 = 11223696^2 + 2657095^2 .
It is a cyclic number.
It is not a de Polignac number, because 133031505739441 - 27 = 133031505739313 is a prime.
It is not a weakly prime, because it can be changed into another prime (133031505739471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515752869720 + 66515752869721.
It is an arithmetic number, because the mean of its divisors is an integer number (66515752869721).
Almost surely, 2133031505739441 is an apocalyptic number.
It is an amenable number.
133031505739441 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031505739441 is an equidigital number, since it uses as much as digits as its factorization.
133031505739441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2041200, while the sum is 49.
The spelling of 133031505739441 in words is "one hundred thirty-three trillion, thirty-one billion, five hundred five million, seven hundred thirty-nine thousand, four hundred forty-one".
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