Base | Representation |
---|---|
bin | 10011010110111101111… |
… | …010011111111001100101 |
3 | 11201011211001201011101020 |
4 | 103112331322133321211 |
5 | 133244004231421201 |
6 | 2455051244521353 |
7 | 165053562654315 |
oct | 23267572377145 |
9 | 4634731634336 |
10 | 1330331123301 |
11 | 473210268044 |
12 | 1959b1250259 |
13 | 985acc6668b |
14 | 48561989445 |
15 | 24911b59a36 |
hex | 135bde9fe65 |
1330331123301 has 4 divisors (see below), whose sum is σ = 1773774831072. Its totient is φ = 886887415532.
The previous prime is 1330331123263. The next prime is 1330331123321. The reversal of 1330331123301 is 1033211330331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1330331123301 - 29 = 1330331122789 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330331123321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221721853881 + ... + 221721853886.
It is an arithmetic number, because the mean of its divisors is an integer number (443443707768).
Almost surely, 21330331123301 is an apocalyptic number.
It is an amenable number.
1330331123301 is a deficient number, since it is larger than the sum of its proper divisors (443443707771).
1330331123301 is an equidigital number, since it uses as much as digits as its factorization.
1330331123301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 443443707770.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 1330331123301 its reverse (1033211330331), we get a palindrome (2363542453632).
The spelling of 1330331123301 in words is "one trillion, three hundred thirty billion, three hundred thirty-one million, one hundred twenty-three thousand, three hundred one".
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