1330333400041 has 4 divisors (see below), whose sum is σ = 1330360808832. Its totient is φ = 1330305991252.

The previous prime is 1330333399987. The next prime is 1330333400047. The reversal of 1330333400041 is 1400043330331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330333400041 - 2¹¹ = 1330333397993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330333399979 and 1330333400015.

It is not an unprimeable number, because it can be changed into a prime (1330333400047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13631461 + ... + 13728706.

It is an arithmetic number, because the mean of its divisors is an integer number (332590202208).

Almost surely, 2^{1330333400041} is an apocalyptic number.

It is an amenable number.

1330333400041 is a deficient number, since it is larger than the sum of its proper divisors (27408791).

1330333400041 is an equidigital number, since it uses as much as digits as its factorization.

1330333400041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27408790.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 1330333400041 its reverse (1400043330331), we get a palindrome (2730376730372).

The spelling of 1330333400041 in words is "one trillion, three hundred thirty billion, three hundred thirty-three million, four hundred thousand, forty-one".