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133034020121 is a prime number
BaseRepresentation
bin111101111100101110…
…0100000110100011001
3110201101100222102210102
41323321130200310121
54134423202120441
6141040500425145
712416464341032
oct1737134406431
9421340872712
10133034020121
1151468266382
12219489a81b5
13c71163ab02
146620409a89
1536d93c769b
hex1ef9720d19

133034020121 has 2 divisors, whose sum is σ = 133034020122. Its totient is φ = 133034020120.

The previous prime is 133034020099. The next prime is 133034020139. The reversal of 133034020121 is 121020430331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96093180121 + 36940840000 = 309989^2 + 192200^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133034020121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133034020093 and 133034020102.

It is not a weakly prime, because it can be changed into another prime (133034020321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66517010060 + 66517010061.

It is an arithmetic number, because the mean of its divisors is an integer number (66517010061).

Almost surely, 2133034020121 is an apocalyptic number.

It is an amenable number.

133034020121 is a deficient number, since it is larger than the sum of its proper divisors (1).

133034020121 is an equidigital number, since it uses as much as digits as its factorization.

133034020121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 133034020121 its reverse (121020430331), we get a palindrome (254054450452).

The spelling of 133034020121 in words is "one hundred thirty-three billion, thirty-four million, twenty thousand, one hundred twenty-one".