Base | Representation |
---|---|
bin | 11110001111111001110001… |
… | …100001001010000001010000 |
3 | 122110000221120122011002121011 |
4 | 132033321301201022001100 |
5 | 114414113041203343004 |
6 | 1150535024435540304 |
7 | 40010256012243451 |
oct | 3617716141120120 |
9 | 573027518132534 |
10 | 133034221543504 |
11 | 39430550959066 |
12 | 12b06b0b75a694 |
13 | 59300c4c599c8 |
14 | 24bcc68043128 |
15 | 105a7d334e004 |
hex | 78fe7184a050 |
133034221543504 has 80 divisors (see below), whose sum is σ = 278241017685120. Its totient is φ = 61429764211200.
The previous prime is 133034221543469. The next prime is 133034221543513. The reversal of 133034221543504 is 405345122430331.
It is a super-2 number, since 2×1330342215435042 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 630684454 + ... + 630895354.
It is an arithmetic number, because the mean of its divisors is an integer number (3478012721064).
Almost surely, 2133034221543504 is an apocalyptic number.
It is an amenable number.
133034221543504 is an abundant number, since it is smaller than the sum of its proper divisors (145206796141616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133034221543504 is a wasteful number, since it uses less digits than its factorization.
133034221543504 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 270068 (or 270062 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 133034221543504 its reverse (405345122430331), we get a palindrome (538379343973835).
The spelling of 133034221543504 in words is "one hundred thirty-three trillion, thirty-four billion, two hundred twenty-one million, five hundred forty-three thousand, five hundred four".
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