Base | Representation |
---|---|
bin | 11110001111111111010110… |
… | …100001010100001011100010 |
3 | 122110001112001001110121120210 |
4 | 132033333112201110023202 |
5 | 114414212323012114414 |
6 | 1150541455035514550 |
7 | 40010560311232224 |
oct | 3617772641241342 |
9 | 573045031417523 |
10 | 133040211051234 |
11 | 39433044872953 |
12 | 12b081015b8a56 |
13 | 593083aac0b16 |
14 | 24bd2756c0414 |
15 | 105aa340b2e59 |
hex | 78ffd68542e2 |
133040211051234 has 128 divisors (see below), whose sum is σ = 276134791495680. Its totient is φ = 42712645248000.
The previous prime is 133040211051217. The next prime is 133040211051239. The reversal of 133040211051234 is 432150112040331.
It is a super-3 number, since 3×1330402110512343 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (133040211051239) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4163084784 + ... + 4163116740.
It is an arithmetic number, because the mean of its divisors is an integer number (2157303058560).
Almost surely, 2133040211051234 is an apocalyptic number.
133040211051234 is an abundant number, since it is smaller than the sum of its proper divisors (143094580444446).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133040211051234 is a wasteful number, since it uses less digits than its factorization.
133040211051234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33416.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 133040211051234 its reverse (432150112040331), we get a palindrome (565190323091565).
The spelling of 133040211051234 in words is "one hundred thirty-three trillion, forty billion, two hundred eleven million, fifty-one thousand, two hundred thirty-four".
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