Base | Representation |
---|---|
bin | 10011010111000010101… |
… | …111111001111100000011 |
3 | 11201012000201022221012211 |
4 | 103113002233321330003 |
5 | 133244141012414301 |
6 | 2455103303202551 |
7 | 165055566250201 |
oct | 23270257717403 |
9 | 4635021287184 |
10 | 1330412232451 |
11 | 4732520265a5 |
12 | 195a14446457 |
13 | 985c39c4863 |
14 | 4856c660071 |
15 | 24918d2c051 |
hex | 135c2bf9f03 |
1330412232451 has 2 divisors, whose sum is σ = 1330412232452. Its totient is φ = 1330412232450.
The previous prime is 1330412232407. The next prime is 1330412232467. The reversal of 1330412232451 is 1542322140331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1330412232451 - 223 = 1330403843843 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330412230451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665206116225 + 665206116226.
It is an arithmetic number, because the mean of its divisors is an integer number (665206116226).
Almost surely, 21330412232451 is an apocalyptic number.
1330412232451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330412232451 is an equidigital number, since it uses as much as digits as its factorization.
1330412232451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1330412232451 its reverse (1542322140331), we get a palindrome (2872734372782).
The spelling of 1330412232451 in words is "one trillion, three hundred thirty billion, four hundred twelve million, two hundred thirty-two thousand, four hundred fifty-one".
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