Base | Representation |
---|---|
bin | 11110010000000000010010… |
… | …111011000101110101110011 |
3 | 122110001121122200100011021121 |
4 | 132100000102323011311303 |
5 | 114414221411424104303 |
6 | 1150542143400203111 |
7 | 40010624365012021 |
oct | 3620002273056563 |
9 | 573047580304247 |
10 | 133041224441203 |
11 | 39433514901821 |
12 | 12b08344a69497 |
13 | 593096ca38860 |
14 | 24bd330115711 |
15 | 105aa9303b9bd |
hex | 790012ec5d73 |
133041224441203 has 32 divisors (see below), whose sum is σ = 155090659046400. Its totient is φ = 113101293841536.
The previous prime is 133041224441171. The next prime is 133041224441267. The reversal of 133041224441203 is 302144422140331.
It is not a de Polignac number, because 133041224441203 - 25 = 133041224441171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133041224441603) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18256525 + ... + 24482302.
It is an arithmetic number, because the mean of its divisors is an integer number (4846583095200).
Almost surely, 2133041224441203 is an apocalyptic number.
133041224441203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133041224441203 is a deficient number, since it is larger than the sum of its proper divisors (22049434605197).
133041224441203 is a wasteful number, since it uses less digits than its factorization.
133041224441203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42739251.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 133041224441203 its reverse (302144422140331), we get a palindrome (435185646581534).
The spelling of 133041224441203 in words is "one hundred thirty-three trillion, forty-one billion, two hundred twenty-four million, four hundred forty-one thousand, two hundred three".
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