Base | Representation |
---|---|
bin | 11000110001111110… |
… | …10001110100101011 |
3 | 1021100012002111102111 |
4 | 30120333101310223 |
5 | 204221330040042 |
6 | 10040053543151 |
7 | 650455231231 |
oct | 143077216453 |
9 | 37305074374 |
10 | 13304143147 |
11 | 5707929729 |
12 | 26b3644ab7 |
13 | 13403c0569 |
14 | 902cda951 |
15 | 52cecd517 |
hex | 318fd1d2b |
13304143147 has 2 divisors, whose sum is σ = 13304143148. Its totient is φ = 13304143146.
The previous prime is 13304143063. The next prime is 13304143163. The reversal of 13304143147 is 74134140331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13304143147 - 223 = 13295754539 is a prime.
It is not a weakly prime, because it can be changed into another prime (13304143187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652071573 + 6652071574.
It is an arithmetic number, because the mean of its divisors is an integer number (6652071574).
Almost surely, 213304143147 is an apocalyptic number.
13304143147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13304143147 is an equidigital number, since it uses as much as digits as its factorization.
13304143147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 13304143147 its reverse (74134140331), we get a palindrome (87438283478).
The spelling of 13304143147 in words is "thirteen billion, three hundred four million, one hundred forty-three thousand, one hundred forty-seven".
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