Base | Representation |
---|---|
bin | 10011010111000010111… |
… | …110010000010001111111 |
3 | 11201012000222102001001211 |
4 | 103113002332100101333 |
5 | 133244142443301413 |
6 | 2455103515545251 |
7 | 165055643234566 |
oct | 23270276202177 |
9 | 4635028361054 |
10 | 1330415993983 |
11 | 4732541656aa |
12 | 195a1575b227 |
13 | 985c4710a0b |
14 | 4856cd5cbdd |
15 | 2491932183d |
hex | 135c2f9047f |
1330415993983 has 4 divisors (see below), whose sum is σ = 1331060889888. Its totient is φ = 1329771098080.
The previous prime is 1330415993957. The next prime is 1330415993987. The reversal of 1330415993983 is 3893995140331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330415993983 - 29 = 1330415993471 is a prime.
It is a Smith number, since the sum of its digits (58) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330415993987) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 322444858 + ... + 322448983.
It is an arithmetic number, because the mean of its divisors is an integer number (332765222472).
Almost surely, 21330415993983 is an apocalyptic number.
1330415993983 is a deficient number, since it is larger than the sum of its proper divisors (644895905).
1330415993983 is an equidigital number, since it uses as much as digits as its factorization.
1330415993983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 644895904.
The product of its (nonzero) digits is 9447840, while the sum is 58.
The spelling of 1330415993983 in words is "one trillion, three hundred thirty billion, four hundred fifteen million, nine hundred ninety-three thousand, nine hundred eighty-three".
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