Base | Representation |
---|---|
bin | 1100000110011010001001… |
… | …1111111111101101110000 |
3 | 1202002212120100202111020102 |
4 | 3001212202133333231300 |
5 | 3220434040420342034 |
6 | 44143514455531532 |
7 | 2542125320133344 |
oct | 301464237775560 |
9 | 52085510674212 |
10 | 13304240012144 |
11 | 426a329711964 |
12 | 15aa54b089ba8 |
13 | 75677a061c43 |
14 | 33dd00317624 |
15 | 1811191ca97e |
hex | c19a27ffb70 |
13304240012144 has 20 divisors (see below), whose sum is σ = 25777921234680. Its totient is φ = 6651873241920.
The previous prime is 13304240012143. The next prime is 13304240012179. The reversal of 13304240012144 is 44121004240331.
It is a super-3 number, since 3×133042400121443 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13304240012143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14977574 + ... + 15840965.
It is an arithmetic number, because the mean of its divisors is an integer number (1288896061734).
Almost surely, 213304240012144 is an apocalyptic number.
It is an amenable number.
13304240012144 is a deficient number, since it is larger than the sum of its proper divisors (12473681222536).
13304240012144 is a wasteful number, since it uses less digits than its factorization.
13304240012144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30845528 (or 30845522 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13304240012144 its reverse (44121004240331), we get a palindrome (57425244252475).
The spelling of 13304240012144 in words is "thirteen trillion, three hundred four billion, two hundred forty million, twelve thousand, one hundred forty-four".
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