Base | Representation |
---|---|
bin | 1100000110011010001011… |
… | …0000000111111111011011 |
3 | 1202002212120122201022020112 |
4 | 3001212202300013333123 |
5 | 3220434043011142342 |
6 | 44143515130314535 |
7 | 2542125401103434 |
oct | 301464260077733 |
9 | 52085518638215 |
10 | 13304244240347 |
11 | 426a33103a645 |
12 | 15aa550588a4b |
13 | 75677abb2638 |
14 | 33dd00ad848b |
15 | 181119763682 |
hex | c19a2c07fdb |
13304244240347 has 2 divisors, whose sum is σ = 13304244240348. Its totient is φ = 13304244240346.
The previous prime is 13304244240317. The next prime is 13304244240403. The reversal of 13304244240347 is 74304244240331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13304244240347 - 216 = 13304244174811 is a prime.
It is not a weakly prime, because it can be changed into another prime (13304244240317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652122120173 + 6652122120174.
It is an arithmetic number, because the mean of its divisors is an integer number (6652122120174).
Almost surely, 213304244240347 is an apocalyptic number.
13304244240347 is a deficient number, since it is larger than the sum of its proper divisors (1).
13304244240347 is an equidigital number, since it uses as much as digits as its factorization.
13304244240347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 774144, while the sum is 41.
Adding to 13304244240347 its reverse (74304244240331), we get a palindrome (87608488480678).
The spelling of 13304244240347 in words is "thirteen trillion, three hundred four billion, two hundred forty-four million, two hundred forty thousand, three hundred forty-seven".
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