Base | Representation |
---|---|
bin | 11110010000000001100110… |
… | …111001111001011100110011 |
3 | 122110001202021212120102012222 |
4 | 132100001212321321130303 |
5 | 114414232303123230301 |
6 | 1150542535251311255 |
7 | 40011004324046525 |
oct | 3620014671713463 |
9 | 573052255512188 |
10 | 133042633414451 |
11 | 3943407816a222 |
12 | 12b086788ab52b |
13 | 5930b35909737 |
14 | 24bd4252c1a15 |
15 | 105ab26aa531b |
hex | 790066e79733 |
133042633414451 has 2 divisors, whose sum is σ = 133042633414452. Its totient is φ = 133042633414450.
The previous prime is 133042633414447. The next prime is 133042633414463. The reversal of 133042633414451 is 154414336240331.
It is a weak prime.
It is an emirp because it is prime and its reverse (154414336240331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133042633414451 - 22 = 133042633414447 is a prime.
It is not a weakly prime, because it can be changed into another prime (133042603414451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66521316707225 + 66521316707226.
It is an arithmetic number, because the mean of its divisors is an integer number (66521316707226).
Almost surely, 2133042633414451 is an apocalyptic number.
133042633414451 is a deficient number, since it is larger than the sum of its proper divisors (1).
133042633414451 is an equidigital number, since it uses as much as digits as its factorization.
133042633414451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 44.
Adding to 133042633414451 its reverse (154414336240331), we get a palindrome (287456969654782).
The spelling of 133042633414451 in words is "one hundred thirty-three trillion, forty-two billion, six hundred thirty-three million, four hundred fourteen thousand, four hundred fifty-one".
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