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133045038264451 is a prime number
BaseRepresentation
bin11110010000000011110110…
…001111101011000010000011
3122110001222111110201110020111
4132100003312033223002003
5114414302214243430301
61150544014035452151
740011121034663155
oct3620036617530203
9573058443643214
10133045038264451
11394350a1694665
1212b0902a157057
135931129c02ac1
1424bd5b2844ad5
15105ac17c88551
hex7900f63eb083

133045038264451 has 2 divisors, whose sum is σ = 133045038264452. Its totient is φ = 133045038264450.

The previous prime is 133045038264421. The next prime is 133045038264493. The reversal of 133045038264451 is 154462830540331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133045038264451 - 243 = 124248945242243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133045038264395 and 133045038264404.

It is not a weakly prime, because it can be changed into another prime (133045038264421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66522519132225 + 66522519132226.

It is an arithmetic number, because the mean of its divisors is an integer number (66522519132226).

Almost surely, 2133045038264451 is an apocalyptic number.

133045038264451 is a deficient number, since it is larger than the sum of its proper divisors (1).

133045038264451 is an equidigital number, since it uses as much as digits as its factorization.

133045038264451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4147200, while the sum is 49.

The spelling of 133045038264451 in words is "one hundred thirty-three trillion, forty-five billion, thirty-eight million, two hundred sixty-four thousand, four hundred fifty-one".