Base | Representation |
---|---|
bin | 11110010000000011110110… |
… | …001111101011000010000011 |
3 | 122110001222111110201110020111 |
4 | 132100003312033223002003 |
5 | 114414302214243430301 |
6 | 1150544014035452151 |
7 | 40011121034663155 |
oct | 3620036617530203 |
9 | 573058443643214 |
10 | 133045038264451 |
11 | 394350a1694665 |
12 | 12b0902a157057 |
13 | 5931129c02ac1 |
14 | 24bd5b2844ad5 |
15 | 105ac17c88551 |
hex | 7900f63eb083 |
133045038264451 has 2 divisors, whose sum is σ = 133045038264452. Its totient is φ = 133045038264450.
The previous prime is 133045038264421. The next prime is 133045038264493. The reversal of 133045038264451 is 154462830540331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133045038264451 - 243 = 124248945242243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133045038264395 and 133045038264404.
It is not a weakly prime, because it can be changed into another prime (133045038264421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66522519132225 + 66522519132226.
It is an arithmetic number, because the mean of its divisors is an integer number (66522519132226).
Almost surely, 2133045038264451 is an apocalyptic number.
133045038264451 is a deficient number, since it is larger than the sum of its proper divisors (1).
133045038264451 is an equidigital number, since it uses as much as digits as its factorization.
133045038264451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4147200, while the sum is 49.
The spelling of 133045038264451 in words is "one hundred thirty-three trillion, forty-five billion, thirty-eight million, two hundred sixty-four thousand, four hundred fifty-one".
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