Base | Representation |
---|---|
bin | 110010110000… |
… | …010010101001 |
3 | 221000222000211 |
4 | 302300102221 |
5 | 11401230001 |
6 | 1153101121 |
7 | 221043043 |
oct | 62602251 |
9 | 27028024 |
10 | 13305001 |
11 | 7568276 |
12 | 45577a1 |
13 | 29aaca8 |
14 | 1aa4a93 |
15 | 127c351 |
hex | cb04a9 |
13305001 has 2 divisors, whose sum is σ = 13305002. Its totient is φ = 13305000.
The previous prime is 13304989. The next prime is 13305007. The reversal of 13305001 is 10050331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12816400 + 488601 = 3580^2 + 699^2 .
It is an emirp because it is prime and its reverse (10050331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13305001 - 25 = 13304969 is a prime.
It is a super-2 number, since 2×133050012 = 354046103220002, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13305007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652500 + 6652501.
It is an arithmetic number, because the mean of its divisors is an integer number (6652501).
Almost surely, 213305001 is an apocalyptic number.
It is an amenable number.
13305001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13305001 is an equidigital number, since it uses as much as digits as its factorization.
13305001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 13.
The square root of 13305001 is about 3647.6020890443. The cubic root of 13305001 is about 236.9581427144.
Adding to 13305001 its reverse (10050331), we get a palindrome (23355332).
The spelling of 13305001 in words is "thirteen million, three hundred five thousand, one".
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