Base | Representation |
---|---|
bin | 1100000110011101110110… |
… | …1001000011000100001011 |
3 | 1202002222010111210221012212 |
4 | 3001213131221003010023 |
5 | 3220443103423202112 |
6 | 44144201142455335 |
7 | 2542162026006515 |
oct | 301473551030413 |
9 | 52088114727185 |
10 | 13305232240907 |
11 | 426a798808032 |
12 | 15aa78743454b |
13 | 7568a77aab59 |
14 | 33dd96000bb5 |
15 | 181176374522 |
hex | c19dda4310b |
13305232240907 has 2 divisors, whose sum is σ = 13305232240908. Its totient is φ = 13305232240906.
The previous prime is 13305232240889. The next prime is 13305232240921. The reversal of 13305232240907 is 70904223250331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13305232240907 - 216 = 13305232175371 is a prime.
It is a super-2 number, since 2×133052322409072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13305232200907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652616120453 + 6652616120454.
It is an arithmetic number, because the mean of its divisors is an integer number (6652616120454).
Almost surely, 213305232240907 is an apocalyptic number.
13305232240907 is a deficient number, since it is larger than the sum of its proper divisors (1).
13305232240907 is an equidigital number, since it uses as much as digits as its factorization.
13305232240907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 41.
The spelling of 13305232240907 in words is "thirteen trillion, three hundred five billion, two hundred thirty-two million, two hundred forty thousand, nine hundred seven".
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