133054135323101 has 4 divisors (see below), whose sum is σ = 134425827439932. Its totient is φ = 131682443206272.

The previous prime is 133054135323097. The next prime is 133054135323103. The reversal of 133054135323101 is 101323531450331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 25812597972100 + 107241537351001 = 5080610^2 + 10355749^2 .

It is a cyclic number.

It is not a de Polignac number, because 133054135323101 - 2² = 133054135323097 is a prime.

It is a super-3 number, since 3×133054135323101³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133054135323103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 685846058270 + ... + 685846058463.

It is an arithmetic number, because the mean of its divisors is an integer number (33606456859983).

Almost surely, 2^{133054135323101} is an apocalyptic number.

It is an amenable number.

133054135323101 is a deficient number, since it is larger than the sum of its proper divisors (1371692116831).

133054135323101 is an equidigital number, since it uses as much as digits as its factorization.

133054135323101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1371692116830.

The product of its (nonzero) digits is 48600, while the sum is 35.

Adding to 133054135323101 its reverse (101323531450331), we get a palindrome (234377666773432).

The spelling of 133054135323101 in words is "one hundred thirty-three trillion, fifty-four billion, one hundred thirty-five million, three hundred twenty-three thousand, one hundred one".