Search a number
-
+
133054553414401 is a prime number
BaseRepresentation
bin11110010000001100101101…
…011001000101101100000001
3122110002220001121011011010121
4132100030231121011230001
5114414431211133230101
61150552230142300241
740011605604300133
oct3620145531055401
9573086047134117
10133054553414401
113943913474a653
1212b0aa44887681
135931cb5310b48
1424bdc36437053
15105b0c32c20a1
hex79032d645b01

133054553414401 has 2 divisors, whose sum is σ = 133054553414402. Its totient is φ = 133054553414400.

The previous prime is 133054553414311. The next prime is 133054553414449. The reversal of 133054553414401 is 104414355450331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99417151764225 + 33637401650176 = 9970815^2 + 5799776^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133054553414401 is a prime.

It is not a weakly prime, because it can be changed into another prime (133054553414501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66527276707200 + 66527276707201.

It is an arithmetic number, because the mean of its divisors is an integer number (66527276707201).

Almost surely, 2133054553414401 is an apocalyptic number.

It is an amenable number.

133054553414401 is a deficient number, since it is larger than the sum of its proper divisors (1).

133054553414401 is an equidigital number, since it uses as much as digits as its factorization.

133054553414401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864000, while the sum is 43.

The spelling of 133054553414401 in words is "one hundred thirty-three trillion, fifty-four billion, five hundred fifty-three million, four hundred fourteen thousand, four hundred one".