Base | Representation |
---|---|
bin | 11110010000001100101101… |
… | …011001000101101100000001 |
3 | 122110002220001121011011010121 |
4 | 132100030231121011230001 |
5 | 114414431211133230101 |
6 | 1150552230142300241 |
7 | 40011605604300133 |
oct | 3620145531055401 |
9 | 573086047134117 |
10 | 133054553414401 |
11 | 3943913474a653 |
12 | 12b0aa44887681 |
13 | 5931cb5310b48 |
14 | 24bdc36437053 |
15 | 105b0c32c20a1 |
hex | 79032d645b01 |
133054553414401 has 2 divisors, whose sum is σ = 133054553414402. Its totient is φ = 133054553414400.
The previous prime is 133054553414311. The next prime is 133054553414449. The reversal of 133054553414401 is 104414355450331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99417151764225 + 33637401650176 = 9970815^2 + 5799776^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133054553414401 is a prime.
It is not a weakly prime, because it can be changed into another prime (133054553414501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66527276707200 + 66527276707201.
It is an arithmetic number, because the mean of its divisors is an integer number (66527276707201).
Almost surely, 2133054553414401 is an apocalyptic number.
It is an amenable number.
133054553414401 is a deficient number, since it is larger than the sum of its proper divisors (1).
133054553414401 is an equidigital number, since it uses as much as digits as its factorization.
133054553414401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 133054553414401 in words is "one hundred thirty-three trillion, fifty-four billion, five hundred fifty-three million, four hundred fourteen thousand, four hundred one".
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