Base | Representation |
---|---|
bin | 11110010000010011110010… |
… | …011110111010100000110011 |
3 | 122110010121200100220202010021 |
4 | 132100103302132322200303 |
5 | 114420042243141122324 |
6 | 1150555524331144311 |
7 | 40012265150004436 |
oct | 3620236236724063 |
9 | 573117610822107 |
10 | 133062155020339 |
11 | 39441385649706 |
12 | 12b104065a5097 |
13 | 593292715561c |
14 | 24c0357c3781d |
15 | 105b3ba824ae4 |
hex | 7904f27ba833 |
133062155020339 has 2 divisors, whose sum is σ = 133062155020340. Its totient is φ = 133062155020338.
The previous prime is 133062155020279. The next prime is 133062155020351. The reversal of 133062155020339 is 933020551260331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133062155020339 - 217 = 133062154889267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133062155020295 and 133062155020304.
It is not a weakly prime, because it can be changed into another prime (133062155020369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66531077510169 + 66531077510170.
It is an arithmetic number, because the mean of its divisors is an integer number (66531077510170).
Almost surely, 2133062155020339 is an apocalyptic number.
133062155020339 is a deficient number, since it is larger than the sum of its proper divisors (1).
133062155020339 is an equidigital number, since it uses as much as digits as its factorization.
133062155020339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 43.
The spelling of 133062155020339 in words is "one hundred thirty-three trillion, sixty-two billion, one hundred fifty-five million, twenty thousand, three hundred thirty-nine".
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