Base | Representation |
---|---|
bin | 11000110010010000… |
… | …00010001010011111 |
3 | 1021100100102002210021 |
4 | 30121020002022133 |
5 | 204222422011203 |
6 | 10040215053011 |
7 | 650513600524 |
oct | 143110021237 |
9 | 37310362707 |
10 | 13306438303 |
11 | 5709157054 |
12 | 26b4371167 |
13 | 1340a15142 |
14 | 90333714b |
15 | 52d2d35bd |
hex | 31920229f |
13306438303 has 4 divisors (see below), whose sum is σ = 13312124728. Its totient is φ = 13300751880.
The previous prime is 13306438273. The next prime is 13306438337. The reversal of 13306438303 is 30383460331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13306438303 is a prime.
It is a super-3 number, since 3×133064383033 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13306438363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2839701 + ... + 2844382.
It is an arithmetic number, because the mean of its divisors is an integer number (3328031182).
Almost surely, 213306438303 is an apocalyptic number.
13306438303 is a deficient number, since it is larger than the sum of its proper divisors (5686425).
13306438303 is an equidigital number, since it uses as much as digits as its factorization.
13306438303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5686424.
The product of its (nonzero) digits is 46656, while the sum is 34.
Adding to 13306438303 its reverse (30383460331), we get a palindrome (43689898634).
The spelling of 13306438303 in words is "thirteen billion, three hundred six million, four hundred thirty-eight thousand, three hundred three".
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