Base | Representation |
---|---|
bin | 11110010000010110000000… |
… | …010100011000000010000001 |
3 | 122110010211211012120001101121 |
4 | 132100112000110120002001 |
5 | 114420112131330403322 |
6 | 1151001000414232241 |
7 | 40012411133203543 |
oct | 3620260024300201 |
9 | 573124735501347 |
10 | 133064534622337 |
11 | 3944239689992a |
12 | 12b1096b4b5681 |
13 | 5932c1614b946 |
14 | 24c0501ca7693 |
15 | 105b4a96bbec7 |
hex | 790580518081 |
133064534622337 has 2 divisors, whose sum is σ = 133064534622338. Its totient is φ = 133064534622336.
The previous prime is 133064534622281. The next prime is 133064534622343. The reversal of 133064534622337 is 733226435460331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123496902023056 + 9567632599281 = 11112916^2 + 3093159^2 .
It is a cyclic number.
It is not a de Polignac number, because 133064534622337 - 211 = 133064534620289 is a prime.
It is not a weakly prime, because it can be changed into another prime (133064534622137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66532267311168 + 66532267311169.
It is an arithmetic number, because the mean of its divisors is an integer number (66532267311169).
Almost surely, 2133064534622337 is an apocalyptic number.
It is an amenable number.
133064534622337 is a deficient number, since it is larger than the sum of its proper divisors (1).
133064534622337 is an equidigital number, since it uses as much as digits as its factorization.
133064534622337 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19595520, while the sum is 52.
The spelling of 133064534622337 in words is "one hundred thirty-three trillion, sixty-four billion, five hundred thirty-four million, six hundred twenty-two thousand, three hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •