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133066025435444 = 2233266506358861
BaseRepresentation
bin11110010000010111011001…
…001011011000000100110100
3122110010222200002210012111212
4132100113121023120010310
5114420123210002413234
61151001404351420552
740012463104666463
oct3620273113300464
9573128602705455
10133066025435444
1139442a91374882
1212b11106824758
1359330c2c7548a
1424c0603c989da
15105b5454ee5ce
hex7905d92d8134

133066025435444 has 6 divisors (see below), whose sum is σ = 232865544512034. Its totient is φ = 66533012717720.

The previous prime is 133066025435393. The next prime is 133066025435597. The reversal of 133066025435444 is 444534520660331.

It can be written as a sum of positive squares in only one way, i.e., 132284502250000 + 781523185444 = 11501500^2 + 884038^2 .

It is a super-2 number, since 2×1330660254354442 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133066025435392 and 133066025435401.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16633253179427 + ... + 16633253179434.

It is an arithmetic number, because the mean of its divisors is an integer number (38810924085339).

Almost surely, 2133066025435444 is an apocalyptic number.

It is an amenable number.

133066025435444 is a deficient number, since it is larger than the sum of its proper divisors (99799519076590).

133066025435444 is a wasteful number, since it uses less digits than its factorization.

133066025435444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33266506358865 (or 33266506358863 counting only the distinct ones).

The product of its (nonzero) digits is 12441600, while the sum is 50.

The spelling of 133066025435444 in words is "one hundred thirty-three trillion, sixty-six billion, twenty-five million, four hundred thirty-five thousand, four hundred forty-four".

Divisors: 1 2 4 33266506358861 66533012717722 133066025435444