Base | Representation |
---|---|
bin | 1100000110101101110010… |
… | …1111001100111111010001 |
3 | 1202010101011210000111000221 |
4 | 3001223130233030333101 |
5 | 3221030340040410442 |
6 | 44150145545513041 |
7 | 2542403054515144 |
oct | 301533457147721 |
9 | 52111153014027 |
10 | 13309512044497 |
11 | 4271594630899 |
12 | 15ab5807a2781 |
13 | 75710a378706 |
14 | 34028058c05b |
15 | 181326e69467 |
hex | c1adcbccfd1 |
13309512044497 has 2 divisors, whose sum is σ = 13309512044498. Its totient is φ = 13309512044496.
The previous prime is 13309512044341. The next prime is 13309512044503. The reversal of 13309512044497 is 79444021590331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11347674814161 + 1961837230336 = 3368631^2 + 1400656^2 .
It is a cyclic number.
It is not a de Polignac number, because 13309512044497 - 215 = 13309512011729 is a prime.
It is a super-2 number, since 2×133095120444972 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13349512044497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6654756022248 + 6654756022249.
It is an arithmetic number, because the mean of its divisors is an integer number (6654756022249).
Almost surely, 213309512044497 is an apocalyptic number.
It is an amenable number.
13309512044497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13309512044497 is an equidigital number, since it uses as much as digits as its factorization.
13309512044497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3265920, while the sum is 52.
The spelling of 13309512044497 in words is "thirteen trillion, three hundred nine billion, five hundred twelve million, forty-four thousand, four hundred ninety-seven".
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