Base | Representation |
---|---|
bin | 1100000110101111101010… |
… | …0110010001011111100011 |
3 | 1202010102110200200200102001 |
4 | 3001223322212101133203 |
5 | 3221032401313121011 |
6 | 44150311403304431 |
7 | 2542421346654412 |
oct | 301537246213743 |
9 | 52112420620361 |
10 | 13310013020131 |
11 | 42718213a4243 |
12 | 15ab6a051b117 |
13 | 75718a0b28b9 |
14 | 3402cad19479 |
15 | 181355e267c1 |
hex | c1afa9917e3 |
13310013020131 has 2 divisors, whose sum is σ = 13310013020132. Its totient is φ = 13310013020130.
The previous prime is 13310013020111. The next prime is 13310013020153. The reversal of 13310013020131 is 13102031001331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13310013020131 - 223 = 13310004631523 is a prime.
It is a super-2 number, since 2×133100130201312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13310013020099 and 13310013020108.
It is not a weakly prime, because it can be changed into another prime (13310013020111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655006510065 + 6655006510066.
It is an arithmetic number, because the mean of its divisors is an integer number (6655006510066).
Almost surely, 213310013020131 is an apocalyptic number.
13310013020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310013020131 is an equidigital number, since it uses as much as digits as its factorization.
13310013020131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13310013020131 its reverse (13102031001331), we get a palindrome (26412044021462).
The spelling of 13310013020131 in words is "thirteen trillion, three hundred ten billion, thirteen million, twenty thousand, one hundred thirty-one".
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