133100279531 has 2 divisors, whose sum is σ = 133100279532. Its totient is φ = 133100279530.

The previous prime is 133100279497. The next prime is 133100279563. The reversal of 133100279531 is 135972001331.

It is a strong prime.

It is an emirp because it is prime and its reverse (135972001331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133100279531 is a prime.

It is a super-2 number, since 2×133100279531² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133100279491 and 133100279500.

It is not a weakly prime, because it can be changed into another prime (133100279591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550139765 + 66550139766.

It is an arithmetic number, because the mean of its divisors is an integer number (66550139766).

Almost surely, 2^133100279531 is an apocalyptic number.

133100279531 is a deficient number, since it is larger than the sum of its proper divisors (1).

133100279531 is an equidigital number, since it uses as much as digits as its factorization.

133100279531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17010, while the sum is 35.

The spelling of 133100279531 in words is "one hundred thirty-three billion, one hundred million, two hundred seventy-nine thousand, five hundred thirty-one".