Base | Representation |
---|---|
bin | 11110010000111000000101… |
… | …101100101011011011010010 |
3 | 122110021100021202011121112112 |
4 | 132100320011230223123102 |
5 | 114421212104304220310 |
6 | 1151025452125225322 |
7 | 40015145063510201 |
oct | 3620700554533322 |
9 | 573240252147475 |
10 | 133101132101330 |
11 | 3945696714a538 |
12 | 12b17a83a02242 |
13 | 59364c9304a63 |
14 | 24c21b460d238 |
15 | 105c3ec5ee705 |
hex | 790e05b2b6d2 |
133101132101330 has 8 divisors (see below), whose sum is σ = 239582037782412. Its totient is φ = 53240452840528.
The previous prime is 133101132101309. The next prime is 133101132101359. The reversal of 133101132101330 is 33101231101331.
It can be written as a sum of positive squares in 2 ways, for example, as 124758110013289 + 8343022088041 = 11169517^2 + 2888429^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1331011321013302 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133101132101296 and 133101132101305.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6655056605057 + ... + 6655056605076.
Almost surely, 2133101132101330 is an apocalyptic number.
133101132101330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133101132101330 is a deficient number, since it is larger than the sum of its proper divisors (106480905681082).
133101132101330 is a wasteful number, since it uses less digits than its factorization.
133101132101330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13310113210140.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 133101132101330 its reverse (33101231101331), we get a palindrome (166202363202661).
Subtracting from 133101132101330 its reverse (33101231101331), we obtain a palindrome (99999900999999).
The spelling of 133101132101330 in words is "one hundred thirty-three trillion, one hundred one billion, one hundred thirty-two million, one hundred one thousand, three hundred thirty".
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