13310140003 has 2 divisors, whose sum is σ = 13310140004. Its totient is φ = 13310140002.

The previous prime is 13310139991. The next prime is 13310140049. The reversal of 13310140003 is 30004101331.

13310140003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13310140003 - 2¹³ = 13310131811 is a prime.

It is not a weakly prime, because it can be changed into another prime (13310140303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655070001 + 6655070002.

It is an arithmetic number, because the mean of its divisors is an integer number (6655070002).

Almost surely, 2^13310140003 is an apocalyptic number.

13310140003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310140003 is an equidigital number, since it uses as much as digits as its factorization.

13310140003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13310140003 its reverse (30004101331), we get a palindrome (43314241334).

The spelling of 13310140003 in words is "thirteen billion, three hundred ten million, one hundred forty thousand, three".