Base | Representation |
---|---|
bin | 1100000110110000010111… |
… | …0111001011011011100001 |
3 | 1202010102221212021220120222 |
4 | 3001230011313023123201 |
5 | 3221033243203013441 |
6 | 44150342234012425 |
7 | 2542426133166404 |
oct | 301540567133341 |
9 | 52112855256528 |
10 | 13310202001121 |
11 | 4271909040483 |
12 | 15ab733877115 |
13 | 7571ba2ac57c |
14 | 34030806dd3b |
15 | 181367805d4b |
hex | c1b05dcb6e1 |
13310202001121 has 2 divisors, whose sum is σ = 13310202001122. Its totient is φ = 13310202001120.
The previous prime is 13310202001093. The next prime is 13310202001157. The reversal of 13310202001121 is 12110020201331.
13310202001121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7669880997025 + 5640321004096 = 2769455^2 + 2374936^2 .
It is a cyclic number.
It is not a de Polignac number, because 13310202001121 - 234 = 13293022131937 is a prime.
It is a super-2 number, since 2×133102020011212 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13310202001121.
It is not a weakly prime, because it can be changed into another prime (13310202031121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655101000560 + 6655101000561.
It is an arithmetic number, because the mean of its divisors is an integer number (6655101000561).
Almost surely, 213310202001121 is an apocalyptic number.
It is an amenable number.
13310202001121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310202001121 is an equidigital number, since it uses as much as digits as its factorization.
13310202001121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13310202001121 its reverse (12110020201331), we get a palindrome (25420222202452).
The spelling of 13310202001121 in words is "thirteen trillion, three hundred ten billion, two hundred two million, one thousand, one hundred twenty-one".
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