Base | Representation |
---|---|
bin | 1100000110110000011100… |
… | …0000001001100100101011 |
3 | 1202010110000012021202111222 |
4 | 3001230013000021210223 |
5 | 3221033313102130102 |
6 | 44150344200012255 |
7 | 2542426454606663 |
oct | 301540700114453 |
9 | 52113005252458 |
10 | 13310221130027 |
11 | 4271918916298 |
12 | 15ab73a16108b |
13 | 7571c1249353 |
14 | 34030a80d1a3 |
15 | 181369333aa2 |
hex | c1b0700992b |
13310221130027 has 2 divisors, whose sum is σ = 13310221130028. Its totient is φ = 13310221130026.
The previous prime is 13310221129991. The next prime is 13310221130039. The reversal of 13310221130027 is 72003112201331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13310221130027 - 28 = 13310221129771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13310221129978 and 13310221130005.
It is not a weakly prime, because it can be changed into another prime (13310221130527) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655110565013 + 6655110565014.
It is an arithmetic number, because the mean of its divisors is an integer number (6655110565014).
Almost surely, 213310221130027 is an apocalyptic number.
13310221130027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310221130027 is an equidigital number, since it uses as much as digits as its factorization.
13310221130027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 13310221130027 its reverse (72003112201331), we get a palindrome (85313333331358).
The spelling of 13310221130027 in words is "thirteen trillion, three hundred ten billion, two hundred twenty-one million, one hundred thirty thousand, twenty-seven".
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