Base | Representation |
---|---|
bin | 100111101010101… |
… | …1110011111101001 |
3 | 10102202120022220011 |
4 | 1033111132133221 |
5 | 10211220424433 |
6 | 340024331521 |
7 | 44661365626 |
oct | 11725363751 |
9 | 3382508804 |
10 | 1331029993 |
11 | 623371597 |
12 | 311913ba1 |
13 | 1829b0a17 |
14 | c8abb34d |
15 | 7bcbe3cd |
hex | 4f55e7e9 |
1331029993 has 2 divisors, whose sum is σ = 1331029994. Its totient is φ = 1331029992.
The previous prime is 1331029961. The next prime is 1331030021. The reversal of 1331029993 is 3999201331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1313120169 + 17909824 = 36237^2 + 4232^2 .
It is an emirp because it is prime and its reverse (3999201331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1331029993 - 25 = 1331029961 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331029493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665514996 + 665514997.
It is an arithmetic number, because the mean of its divisors is an integer number (665514997).
Almost surely, 21331029993 is an apocalyptic number.
It is an amenable number.
1331029993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331029993 is an equidigital number, since it uses as much as digits as its factorization.
1331029993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39366, while the sum is 40.
The square root of 1331029993 is about 36483.2837474918. The cubic root of 1331029993 is about 1100.0082624724.
The spelling of 1331029993 in words is "one billion, three hundred thirty-one million, twenty-nine thousand, nine hundred ninety-three".
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