Base | Representation |
---|---|
bin | 10011010111100111101… |
… | …000101111111100000001 |
3 | 11201020121211212100101011 |
4 | 103113213220233330001 |
5 | 133301422431112343 |
6 | 2455244532040521 |
7 | 165110122535065 |
oct | 23274750577401 |
9 | 4636554770334 |
10 | 1331031113473 |
11 | 47353a400016 |
12 | 195b67763141 |
13 | 98691ca1449 |
14 | 485ca91daa5 |
15 | 2495332929d |
hex | 135e7a2ff01 |
1331031113473 has 2 divisors, whose sum is σ = 1331031113474. Its totient is φ = 1331031113472.
The previous prime is 1331031113411. The next prime is 1331031113483. The reversal of 1331031113473 is 3743111301331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1331030612209 + 501264 = 1153703^2 + 708^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331031113473 - 217 = 1331030982401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331031113483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665515556736 + 665515556737.
It is an arithmetic number, because the mean of its divisors is an integer number (665515556737).
Almost surely, 21331031113473 is an apocalyptic number.
It is an amenable number.
1331031113473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331031113473 is an equidigital number, since it uses as much as digits as its factorization.
1331031113473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
The spelling of 1331031113473 in words is "one trillion, three hundred thirty-one billion, thirty-one million, one hundred thirteen thousand, four hundred seventy-three".
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