Base | Representation |
---|---|
bin | 1100000110110000110110… |
… | …1100000101110001110001 |
3 | 1202010110022000101012102001 |
4 | 3001230031230011301301 |
5 | 3221034030311441423 |
6 | 44150403244254001 |
7 | 2542432316260315 |
oct | 301541554056161 |
9 | 52113260335361 |
10 | 13310333312113 |
11 | 4271976178362 |
12 | 15ab76b841301 |
13 | 75720b566996 |
14 | 34031b691b45 |
15 | 1813740e2cad |
hex | c1b0db05c71 |
13310333312113 has 2 divisors, whose sum is σ = 13310333312114. Its totient is φ = 13310333312112.
The previous prime is 13310333312063. The next prime is 13310333312137. The reversal of 13310333312113 is 31121333301331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9987066293824 + 3323267018289 = 3160232^2 + 1822983^2 .
It is a cyclic number.
It is not a de Polignac number, because 13310333312113 - 29 = 13310333311601 is a prime.
It is not a weakly prime, because it can be changed into another prime (13310333319113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655166656056 + 6655166656057.
It is an arithmetic number, because the mean of its divisors is an integer number (6655166656057).
Almost surely, 213310333312113 is an apocalyptic number.
It is an amenable number.
13310333312113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310333312113 is an equidigital number, since it uses as much as digits as its factorization.
13310333312113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 28.
Adding to 13310333312113 its reverse (31121333301331), we get a palindrome (44431666613444).
The spelling of 13310333312113 in words is "thirteen trillion, three hundred ten billion, three hundred thirty-three million, three hundred twelve thousand, one hundred thirteen".
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