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1331040157 = 6719866271
BaseRepresentation
bin100111101010110…
…0000111110011101
310102202120211211121
41033111200332131
510211221241112
6340024450541
744661440356
oct11725407635
93382524747
101331040157
11623379197
12311919a51
131829b5535
14c8ac0d2d
157bcc2407
hex4f560f9d

1331040157 has 4 divisors (see below), whose sum is σ = 1350906496. Its totient is φ = 1311173820.

The previous prime is 1331040119. The next prime is 1331040167. The reversal of 1331040157 is 7510401331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331040157 - 211 = 1331038109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331040167) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9933069 + ... + 9933202.

It is an arithmetic number, because the mean of its divisors is an integer number (337726624).

Almost surely, 21331040157 is an apocalyptic number.

It is an amenable number.

1331040157 is a deficient number, since it is larger than the sum of its proper divisors (19866339).

1331040157 is an equidigital number, since it uses as much as digits as its factorization.

1331040157 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19866338.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 1331040157 is about 36483.4230438976. The cubic root of 1331040157 is about 1100.0110624232.

Adding to 1331040157 its reverse (7510401331), we get a palindrome (8841441488).

The spelling of 1331040157 in words is "one billion, three hundred thirty-one million, forty thousand, one hundred fifty-seven".

Divisors: 1 67 19866271 1331040157