Base | Representation |
---|---|
bin | 1100000110110001010001… |
… | …0000001000101001101011 |
3 | 1202010110120200120111000112 |
4 | 3001230110100020221223 |
5 | 3221034242004034423 |
6 | 44150422220324535 |
7 | 2542435124230301 |
oct | 301542420105153 |
9 | 52113520514015 |
10 | 13310443424363 |
11 | 4271a22346318 |
12 | 15ab7a06a374b |
13 | 75722830b167 |
14 | 34032c156271 |
15 | 18137dae3a78 |
hex | c1b14408a6b |
13310443424363 has 2 divisors, whose sum is σ = 13310443424364. Its totient is φ = 13310443424362.
The previous prime is 13310443424321. The next prime is 13310443424417. The reversal of 13310443424363 is 36342434401331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13310443424363 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13310443424363.
It is not a weakly prime, because it can be changed into another prime (13310443424563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655221712181 + 6655221712182.
It is an arithmetic number, because the mean of its divisors is an integer number (6655221712182).
Almost surely, 213310443424363 is an apocalyptic number.
13310443424363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310443424363 is an equidigital number, since it uses as much as digits as its factorization.
13310443424363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 41.
Adding to 13310443424363 its reverse (36342434401331), we get a palindrome (49652877825694).
The spelling of 13310443424363 in words is "thirteen trillion, three hundred ten billion, four hundred forty-three million, four hundred twenty-four thousand, three hundred sixty-three".
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